Question

What is the maximum number of moles of KClO3 that could form in the combination of 6.0 moles of Cl2 with 9.0 moles of KOH?

Answer 1

Since the mole ratio of Cl2 : KOH is 3 : 6, then 6 moles of Cl2 would require 12 moles KOH. There are only 9 moles KOH, so KOH is limiting. Now look at the mole ratio of KOH : KClO3 and it is 6 : 1. So, for every 6 moles KOH, you get 1 mole KClO3. From 9 moles KOH you will get 1/6 x 9 = 1.5mol KClO3.

This is the max number of moles.