Question

what is the maximum possible number of electron in nitrogen that can have the magnetic quantum no m=+1

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Answer 1

Explanation:

Out of 6 electrons in 2p and 3p must have an electron with m=+1 and s=−

2

1

but in 3d− subshell an orbit having m=+1 may have spin quantum no. −

2

1

or +

2

1

.

Therefore, minimum and maximum possible values are 2 and 3 respectively.

Answer 2

Answer:

Only 1 electron is possible in nitrogen that can have a magnetic quantum number = +1

Explanation:

Nitrogen fall in the fifteenth group of the periodic table. As we see the electronic configuration nitrogen is $\[1{s^2}2{s^2}2{p^3}\]$

Electronic distribution of 2p orbital is

n = 2

l = 1

The possible value of l = -1, 0 , +1

$\[\begin{gathered} \boxed \uparrow \boxed \uparrow \boxed \uparrow \hfill \\ ^{^{^{^{^{^{^{^{ - 1{\text{ \ \ }}0{\text{ \ \ }} + 1}}}}}}}} \hfill \\ \end{gathered} \]$

Therefore, only 1 electron is possible in nitrogen with magnetic quantum number +1.