Question

what is the maximum possible range of a projectile of mass 5kg fired with 10m/s?​

Answer 1

Explanation:

Range=u^2sin2theta/g

=(10)^2 sin2theta/10

100sin2 theta/10

= 10 sin2theta

if theta is given in your question then put the value of theta

Answer 2

Answer:

Explanation: The formula for horizontal range is R = v2 (sin 2θ)/g. Here, v = 25, θ = 60°, g = 10. Hence, on solving we will get range as 54.13 m.

Explanation:

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