Question

What is the maximum power that can be drawn from a 12v battery source that has an internal resistance of 0.25 ohms

Answer 1

Answer: 144W

Explanation:

P = V²/4R (internal + external resistance)

Answer 2

Answer:

The maximum power, P, drawn from the battery measured is $288W$.

Explanation:

Given,

The battery's given voltage, V =$12V$

The battery's given internal resistance, r = $0.25\Omega$

The maximum power drawn from the battery, P =?

As we know,

According to the maximum power transfer theorem, the power delivered to the load will be maximum when;

• Load resistance ($r^{'}$) = internal resistance of battery (r) = $0.25\Omega$

Therefore,

• The total resistance, R = $r^{'} + r$ = $0.25 + 0.25$ = $0.5\Omega$

Now,

• Power = $\frac{V^{2} }{R}$ = $\frac{(12)^{2} }{0.5}$ = $288W$

Hence, the maximum power drawn from the battery, P = $288W$.