Question

What is the maximum resistance make available using two, 10 ohm resistors? How are they to be connected for this?

Answer 1

Answer:-

• Maximum Resistance will be 20 ohms.
• We connect these resistors in series .

Explanation :-

As it is given that the resistance of each Resistor is 10ohm

we have to calculate the maximum resistance by using the given two resistor .

If we connect these resistors in series combination then we will get the maximum equivalent resistance .

As we know that Equivalent resistance in the series combination is calculated by the sum of resistance of individual Resistors .

So, the equivalent resistance in series .

→ Req = R1 + R1

→ Req = 10 + 10

→ Req = 20 ohms .

• Hence, the maximum equivalent resistance we will get by combining the given Resistor in series combination is 20 ohm.

Answer 2

Answer:

Given :-

• The resístance of each resístors is 10 ohm resistors.

To Find :-

• What is the maximum resístance make available using two resístors.

Formula Used :-

$\clubsuit$ Equívalent Resístance for series connection :

$\mapsto \sf\boxed{\bold{\pink{R_{eq} =\: R_1 + R_2\: +\: . . . .\: +\: R_n}}}$

where,

• $\sf R_{eq}$ = Equívalent Resístance
• $\sf R_1$ = Resístance of resístors R₁
• $\sf R_2$ = Resístance of resístors R₂

Solution :-

Given :

$\bigstar\: \rm{\bold{Resistance\: of\: resistors\: (R_1) =\: 10\: \Omega}}$

$\bigstar\: \rm{\bold{Resistance\: of\: resistors\: (R_2) =\: 10\: \Omega}}$

According to the question by using the formula we get,

$\longrightarrow \sf R_{eq} =\: R_1 + R_2$

$\longrightarrow \sf R_{eq} =\: 10\: \Omega + 10\: \Omega$

$\longrightarrow \sf R_{eq} =\: (10 + 10)\: \Omega$

$\longrightarrow \sf R_{eq} =\: (20)\: \Omega$

$\longrightarrow \sf\bold{\red{R_{eq} =\: 20\: \Omega}}$

$\therefore$ The maximum resístance is 20 Ω . It is connected by equívalent resístance of series connection.

EXTRA INFORMATION :-

$\clubsuit$ Equívalent Resístance for párallel connection :

$\mapsto \sf\boxed{\bold{\pink{\dfrac{1}{R_{eq}} =\: \dfrac{1}{R_1} + \dfrac{1}{R_2}\: +\: . . . .\: +\: \dfrac{1}{R_n}}}}$

where,

• $\sf R_{eq}$ = Equívalent Resístance
• $\sf R_1$ = Resístance of resístors R₁
• $\sf R_2$ = Resístance of resístors R₂