Question

What is the maximum sum of the series 60,56,52,48....

Answer 1

Step-by-step explanation:

I think right answer is 60

Answer 2

Answer:

the maximum sum of the series 60,56,52,48....  is   450

Step-by-step explanation:

the series given :

60,56,52,48....

so each one is having a difference of '-4'

so the series given is in arithmetic progression AP

because 60-56 = 56-52

4 = 4

let the series be  60,56,52,48..   0

here the first term is  a= 60

difference d = ( 56-60)

d = - 4

the last term formula is

Tₙ = a + (n - 1)d

Tₙ = 0

where n = number of terms present in the given series

substitute values of 'a' and 'd' in formula

Tₙ = 60 + ( n - 1)(-4)

0 = 60 + (n - 1)(-4)

0 = 60 - 4n + 4

0 = 64 - 4n

4n = 60

n = 60/4

n = 15

number of terms in given series is n= 15

maximum sum of the series 60,56,52,48....   is  

Sₙ = (n/2)(a + Tₙ)

= (15/2)(60 + 0)

= (15/2)(60)

= (15)(60/2)

= (15)(30)

= 450

the maximum sum of the series 60,56,52,48....  is   450