what is the maximum velocity of particle if its SHM is y=0.05sin(100t+π/2)cm
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y = 0.05sin(100t + π/2) cm
Compare it with general SHM equation
y = A sin(ωt + φ)
We can say
A = 0.05 cm
ω = 100 rad/s
Maximum velocity = A ω
= 0.05 cm × 100 rad/s
= 5 cm/s
∴ Maximum Velocity of particle is 5 cm/s
Compare it with general SHM equation
y = A sin(ωt + φ)
We can say
A = 0.05 cm
ω = 100 rad/s
Maximum velocity = A ω
= 0.05 cm × 100 rad/s
= 5 cm/s
∴ Maximum Velocity of particle is 5 cm/s
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