Question

What is the maximum wavelength line in the lyman series of he+ ion?

Answer 1

Explanation:

Just put value of 1/RH = 912 Angstroms to get value of maximum wavelength.

here's the answer and hope this helps you.

Answer 2

Answer:

    The maximum wavelength of Lyman series of he+ ion is $\frac{1}{3R}$.

Explanation:

For He$^{+}$, z=2

   Wavenumber  v=1/λ

                              $=RZ^{2} [\frac{1}{n^{2}_{1} }- \frac{1}{n^{2}_{2} }]$

      For the Lyman series, $n_{1}=1$ and for maximum wavelength, $n_{2}$ has to be the smallest possible energy level.

                              $n_{2}=2$

               Therefore,

                           1/λmax$=4R[\frac{1}{1}-\frac{1}{4}]$

                                         $=\frac{1}{3R}$