What is the maximum wavelength of incident light that can produce photoelectrons from silver?
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The energy of a photon of wavelength WL is:
E = h*c/WL , where h = Planck's constant
c = speed of light
So the larger the WL, the lower the energy.
One finds the maximum WL by setting the minimum energy to:
E = phi = 4.64 eV
Therefore,
hc/WL = E = phi = 4.64 eV
WL = hc/(4.64 eV)
h = 4.315 e-15 (eV*s)
c = 3e8 (m)
So
WL = 3*4.135*e-7 (m)
= 1.24e-6 (m)
E = h*c/WL , where h = Planck's constant
c = speed of light
So the larger the WL, the lower the energy.
One finds the maximum WL by setting the minimum energy to:
E = phi = 4.64 eV
Therefore,
hc/WL = E = phi = 4.64 eV
WL = hc/(4.64 eV)
h = 4.315 e-15 (eV*s)
c = 3e8 (m)
So
WL = 3*4.135*e-7 (m)
= 1.24e-6 (m)
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