What is the maximum weight of silver chloride that can be precipitated from 8.5 gm of silver nitrate by the addition of hydrochloric acid
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Answer:
AgNO
3
+HCl→AgCl+HNO
3
1 1 1
170 143.5
Mass of AgCl formed =143.5×0.34/170=0.287gm
Explanation:
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