What is the maximum weight that can be lowered by a person who can exert a 500 n pull on a rope if the rope is wrapped 2 turns around a horizontal spur? Coefficient of friction between spur and rope is 0.3:?
Answers
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Answer:
Maximum weight = 300 N
Explanation:
We apply the idea of mechnical advantage to this issue.
A mechanical advantage is produced when the cord is wrapped around the skid, enabling the person to apply more force than he could by pulling directly. The quantity of rope turns coiled around the skid determines the mechanical edge.
In this instance, a mechanical edge of two is provided by the rope's two turns of wrapping around the skid. This indicates that the weight decreases by 2N for every 1N of force applied by the person.
The following algorithm is used to determine the highest weight that can be lowered:
Maximum weight equals (tractive exertion) times (mechanical advantage) multiplied by (coefficient of friction)
Plugging in the given values, we get:
Maximum weight = (500 N) x (2) x (0.3)
Maximum weight = 300 N
Learn more about Coefficient of friction :
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