Math, asked by mohitshirpurka4275, 7 months ago

What is the mean deviation of the first 10 numbers of the fibanocci sequence?

Answers

Answered by RvChaudharY50
23

Question :- What is the mean deviation of the first 10 numbers of the fibanocci sequence ?

Answer :-

Fibanocci sequence :-

  • 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ... The next number is found by adding up the two numbers ... (0+1 = 1, 1 + 1 = 2, 1 + 2 = 3 , 2 + 3 = 5, 3 + 5 = 8 _________)

So,

First 10 terms of fibanocci sequence are = 0, 1, 1, 2, 3, 5, 8, 13, 21, 34 .

Than,

→ sum of first 10 terms of fibanocci sequence will be = 0 + 1 + 1 + 2 + 3 + 5 + 8 + 13 + 21 + 34 = 88 .

Therefore,

→ Mean deviation = (sum of observation) / (Total number of observation .)

→ Mean deviation = (88/10)

→ Mean deviation = 8.8 . (Ans.)

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Answered by nancychaterjeestar29
0

Answer:

The Fibonacci series is a set of integers (the Fibonacci numbers) that will start from zero, followed by a one, then by another one, and then by a series of staticly increasing numbers. The sequence always follows a rule that each number is equal to sum of the next two numbers.

The Fibonacci sequence begins with the following 14 integers:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233 ...

Each number, starting with the three, adheres to the given formula. For example, the seven numbers, 8, is preceded by 3 and 5, which add up to 8.

The sequence can be continued to infinity, using the same formula for each and every number. Some resources show the Fibonacci sequence starting with a one instead of a zero, but this is very uncommon.

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