Question

What is the mean, median, and mode of the following distribution ​

Answer 1

Answer:

this question, total frequency(N) = 5+15+20+30+20+8=98

So,N2=49

If, we calculate cumulative frequency that is equal to or just greater than 49, it comes 70, making 90−99 our median class.

As, 70 is the less than type cumulative frequency corresponding to the class boundary 89.5

So, lower class boundary(l)=89.5

Cumulative frequency of the class preceding the median class(F)=40

Frequency of median class(f)=30

Interval(i)=10

We know, Median =(l+(N2)−Ff)∗i

Putting above values in formula,

Median = 89.5+(49−4030)∗10

=89.5+9∗1030

Median=89.5+3=92.5

Answer 2

Answer:

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