Question

what is the mean proportion between the MPs of (2/7&32/343) and (2&1/5000)?​

Answer 1

Step-by-step explanation:

If three numbers are in continuous proportion then the middle number is called mean proportion. So let the mean proportion between 5:45 will be x. Then

5/x= x/45

=>x2= 45*5

=> x2= 225

=> x= 15

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Answer 2

Answer:2/35

Propotion between two numbers X,Y is $\sqrt{XY}$ Propotion between  Mean propotions of (X,Y) and (Z,A) numbers is $\sqrt[4](\sqrt{XY} * \sqrt{ZA})$

$\sqrt[4]{ (\sqrt{(2/7)*(32/343)}) * \sqrt{(2)*(1/5000)})}$

$\sqrt[4](\sqrt{XY} * \sqrt{ZA})$= √(XY)×√(ZA)=XYZA

(2/7)*(2⁵/7³) = (2⁶/7⁴)

(2/5000)= (1/2500)

(2⁴/7⁴)*(2³/5000)=(2⁴/7⁴) *(1/625)

$\sqrt[4]{(2/7)*(1/5)}$⁴=2/35

Step-by-step explanation: