what is the mean proportion of(X+y)² and (x-y)²
Answers
Answered by
1
Answer:
sorry I don't know the answer
Answered by
10
Let the third proportional to (x² - y²) and (x - y) be P.
Therefore, (x² - y²), (x - y) and P are in proportion.
=> (x² - y²) : (x - y) = (x - y) : P
=> (x² - y²)/(x - y) = (x - y)/P
=> P = (x - y)²/(x² - y²)
=> P = (x - y)(x - y)/(x + y)(x - y)
=> P = (x - y)/(x + y).
Therefore, the third proportional to (x² - y²) and (x - y) is (x - y)/(x + y).
Hope it helps you
Pls mark me brainliest :)
Therefore, (x² - y²), (x - y) and P are in proportion.
=> (x² - y²) : (x - y) = (x - y) : P
=> (x² - y²)/(x - y) = (x - y)/P
=> P = (x - y)²/(x² - y²)
=> P = (x - y)(x - y)/(x + y)(x - y)
=> P = (x - y)/(x + y).
Therefore, the third proportional to (x² - y²) and (x - y) is (x - y)/(x + y).
Hope it helps you
Pls mark me brainliest :)
Similar questions