Question

What is the mean translational kinetic energy of a perfect gas molecule at temperature T?

Answer 1

A perfect gas molecule has only translational K.E.

E = 3/2 kBT

Answer 2

The mean translational kinetic energy of a perfect gas molecule at temperature T

Explanation:

• A perfect gas molecule has only translational Kinetic energy

                           $E= \frac{3}{2}K_BT$

• The translational kinetic energy depends on motion through space, and for a rigid body of constant mass is equal to the product of half the mass times the square of the speed.

• The only difference between rotational and translational kinetic energy is that translational is straight line motion while rotational is not.  

• Whereas The average translational kinetic energy of a molecule of an ideal gas can be found using the formula: The average translational kinetic energy of a single molecule of an ideal gas is (Joules). 2) One mole (mol) of any substance consists of molecules (Avogadro's number).

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