Question

what is the measure of each exterior angle of a regular polygon of 19 sides​

Answer 1

Answer:

18.94⁰

exterior angle of a polygon = 360⁰/no.of side in the regular polgon = 360⁰/19 = 18.94⁰

Answer 2

Answer:

18°56'51"

Step-by-step explanation:

For any regular polygon of sides n:

Total number of internal angles = n

and Total of those n angles measure in ° = $180(n - 2)$

∴ Each of these n angles measure in ° = $\frac{180(n - 2)}{n}$

∴ Each exterior angle measure in ° = $180 - \frac{180(n - 2)}{n}$ = $\frac{360}{n}$

∴ For a regular polygon of 19 sides, each exterior angle measure in ° = $\frac{360}{19}$

=18°56'51"