What is the measure of each interior angle and each exterior angle of a regular pentagon and a regular octagon?
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Step-by-step explanation:
It depends on the no. Of sides of a regular polygon.
Each exterior angle will be 360%/n.
And, interior angle will be sum of angle of
that polygon divided by no. Of sides i.e. (n-2)*180° /n and, Here it is a pentagon i.e. n = 5. So, exterior angles will be 360/5 = 72°.
Interior angles will be (5-2)180%/5 = 3*36 = 108°.
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