Math, asked by aayush2078regmi, 6 hours ago

What is the measures of side AB in a given figure?

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Answered by shakshi015724
0

Step-by-step explanation:

The three angles of a triangle are related in a special way. The sum of their measures is 180\text{°}. Note that we read m\text{∠}A as “the measure of angle A.” So in \text{△}ABC in (Figure),

m\text{∠}A+m\text{∠}B+m\text{∠}C=180\text{°}

Because the perimeter of a figure is the length of its boundary, the perimeter of \text{△}ABC is the sum of the lengths of its three sides.

P=a+b+c

Answered by varshanamukilan
2

Answer: 12 cm

Step-by-step explanation:

This triangle in the adjoining figure is an isosceles triangle, which means two of its sides and two of its angles are equal.

Here, since ∠ B = ∠ C = 62 Degrees, sides AB and AC are equal.

So,

x + 5 = 2x - 2

⇒ x - 2x = -2 - 5

⇒ -x = -7

x = 7

Therefore, the measures of side AB is

x + 5 = 7 + 5 = 12 cm

I hope this helps :)

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