Question

what is the mechanical energy E of the linear oscillator? Given initally, the block position is x=11cm, speed is v=0 and spring constant k=65N/m​

Answer 1

The correct answer is 0.393 Joule.

Explanation:

• Since the position of the block is represented by x and its value is 11 cm while the speed of the block is 0.

• As a result of zero movement, the kinetic energy, in this case, will be zero too.

• But, the block will have potential energy, e = 1/2 x 65 x (0.11)^2 = 0.393 Joule.

• Joule is an SI unit used for energy.

Answer 2

Given that,

Block position x=11 cm

Speed v = 0

Spring constant = 65 N/m

We know that,

Amplitude :

Amplitude is the maximum position of the linear oscillator

So, the amplitude of the spring is

A = 0.11 m

The speed of block is zero then the kinetic energy will be zero.

We need to calculate the mechanical energy of the linear oscillator

Using formula of mechanical energy

$E=\dfrac{1}{2}kA^2$

Where, k = spring constant

A = amplitude

Put the value into the formula

$E=\dfrac{1}{2}\times65\times0.11^2$

$E=0.39325\ J$

Hence, The mechanical energy of the linear oscillator

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Topic : linear oscillator

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