Question

What is the mechanical energy E of the linear oscillator of Problem 1 above. (Initially, the block’s position is x = 11 cm and its speed is v = 0. Spring constant k is 65 N/m

Answer 1

Answer:

0.39J

Explanation:

E=K.E+ P.E

= 0+ 1/2*65*(.11*.11)

= 0.39 J

Answer 2

Answer:

The answer will be  0.393 Joule

Explanation:

According to the problem initially the block is at the position of 11 cm and the speed of it is zero

It is given that the spring constant is 65 N/m

Now as block doesn't move therefore there the kinetic energy will be zero

and only the potential energy will be considered.

Therefore,

the total mechanical energy , e = 1/2 x 65 x (0.11)^2 = 0.393 Joule