Question

What is the mechanical energy E of the linear oscillator of Problem 1 above. (Initially, the block’s position is x = 11 cm and its speed is v = 0. Spring constant k is 65 N/m

Answer 1

Answer:

Total energy will be 0.39325 j

Explanation:

We have to find the total energy

Total energy is given by, total energy = kinetic energy + potential energy

We have given position of the block x = 11 cm = 0.11 m

Spring constant k = 65 N/m

Kinetic energy is given by KE=\frac{1}{2}mv^2=\frac{1}{2}m\times 0^2=0j[/tex]

Potential energy is given by $PE=\frac{1}{2}Kx^2=\frac{1}{2}\times 65\times 0.11^2=0.39325J$

So total energy = 0+0.39325 =0.39325 j