What is the median of 1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 5, 5, 6, 7, 7, 7, 8, 8, 8, 9, 9, 10, 11, 13?
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Just cut 1st and last numbers and take avg of left over numbers
The median is 4
Hope it helps
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Solution:
Constructing a c.f. table,
X f c.f.
1 1 1
2 5 6
3 8 14
4 2 16
5 2 18
6 1 19
7 3 22
8 3 25
9 2 27
10 1 28
11 1 29
13 1 30
N=30
Now,
Median(Md)=(N+1)/2th item
=(30+1)/2th item
=15.5th item
The cf value just greater than 15.5 is 16 and its corresponding value is 4.
So, median(Md)=4
Hope it helps!
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