Question

What is the midpoint of the line segment with
endpoints (-3, 2) and (11,8)?​

Answer 1

Answer:

(4,5)

Step-by-step explanation:

x1+x2÷2=-3+11÷2=4

y1+y2÷2=2+8÷2=5

Answer 2

Answer:

Let two points be A and B such that their coordinates are (-3,2) and (11,8) respectively.

∴ the two points are A(-3,2) and B(11,8)

Let, P(x,y) be the ,midpoints of the AB,

Now since we have to find the midpoints of the line segment AB,

∴P(x,y) = $(\frac{-3+11}{2} ,\frac{2+8}{2} )$

⇒P(x,y) = (4,5)

Hence, the P(4,5) will be the midpoint of the line segment  AB which is joined by (-3,2) and (11,8)

Formula used:-

The coordinates of the midpoints of a line segment is given by

= $\frac{x_{1} +x_{2} }{2} ,\frac{y_{1}+y_{2} }{2}$