Question

What is the minimum distance

between two objects which can be resolved by amicroscope having the visual angle of 300when light of wavelength 500 nm is used?​

Answer 1

$\huge\underline\frak{\fbox{AnSwEr :-}}$

Solution: According to Eq. (7.33) the minimum distance is given by

dmin = 0.61λ /tan b

dmin = 0.61 x 5.0 x 10-7/tan 30o

= 5.28 x 10-7 m.

Answer 2

Answer:

150,000 nm

Step-by-step explanation:

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