What is the minimum electrical force between two charged particles 1 m apart in free space?
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23.04x10^-23N
Using coulomb’s law
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F=kq1q2/r^2 where k=9x10^9
q=1.6x10^-19
r=1m
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Answer:
We know that, F=(1/4πε0)(q^1q^2)/r^2. F will be minimum when q1andq2 are minimum i. e. q1=q2=1.6×10
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