Question

What is the minimum force with which each boy has to pull the rope in order to balance if each girl pulls the rope with a force of 400N​

Answer 1

Explanation:

Let us take acceleartion due to gravity “g" to be 10m/s^2 for ease of calculation.

And let the maximum upward acceleartion dat can be put on the rope be “a"

Now.. Total downward force or the tension in the rope should not exceed 400N

if we draw the F. B. D

We find that the total downward force will be “m(g+a)” where m is the mass hanging.

now this downward force should be equal to the maximum tension the rope can whitsand in the extreme condition.

Now putting evrything n making up a equation we should have ..

=) m(g+a)=400

Plug in the values.. And solve for “a"

=)300+30a=400

=)a=100/30

Therfore required value of maximum acceleartion will be a=10/3

Answer 2

Answer

400N.

Explanation:

Each girl pulls=400N.

F=ma.we don't know mass and acceleration.

balanced force=force from both sides.

:•Girls =400N.

Then boys should be 400N.

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