Question

What is the minimum molecular weight of alkane that exhibit optical isomerism?

Answer 1

Minimum molecular weight of alkane to exhibit optical isomerism is 100gm.

Explanation:

• Alkane must have only single bonds. So the minimum molecular compound of the alkane which exhibits optical isomerism is $C_7H_1_6$ and its respective molecular weight is 100 grams.

• The alkane must contain at least seven carbon atoms as a straight chain at the centre and to each carbon atoms which are at the extreme ends of the chain must be attached with three hydrogen atoms.

• To the carbon atoms which are at the middle of the chain must be attached with two hydrogen atom on either side of the carbon atom.

• This is done to make the carbon atoms form octet configuration.

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