What is the minimum number of carbon atoms required in order to show positional isomerism
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H0LA...
Minimum number of carbons to show position isomerim is 3
and min. no.of carbons to form chain isomerism is 4
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Minimum number of carbons to show position isomerim is 3
and min. no.of carbons to form chain isomerism is 4
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Anonymous:
i know u
But the answer given is 2
2 can never come as answer
Answered by
2
the minimum number is 4
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