What is the minimum number of carbon needed to make an optical isomer (alkene)?
(I know the ans is 7 but how is it 7?)
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Optical isomer is possible if all 4 groups attached to a carbon are different.
Consider a carbon atom.
The first group to be attached can be H (hydrogen atom)
The second group can be a methyl group
The third group can be an ethyl group
The fourth group can be a propyl group
The reason I chose these groups are because they have the minimum number of carbon atoms, and all groups are different. Hence when they are attached to a carbon atom, it satisfies the condition for optical isomerism.
Now to find the number of carbon atoms:
(1 carbon to which the groups are attached) + (1 carbon of methyl) + (2 carbon of ethyl) + (3 carbons of propyl)
= 1+1+2+3
= 7, which is the answer
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