Question

what is the minimum number of square marbles required to tile a floor of length 5 m 78 cm and width 3 m 74 cm?

Answer 1

Convert all to cm units:

5 m 78 cm = 578 cm

3 m 74 cm = 374 cm

Find the Prime Factors:

578 = 2 x 17²

374 = 2 x 11 x 17

Find the HCF:

HCF = 17

Find the number of tiles length wise:

Number of tiles = 578 ÷ 17 = 34 tiles

Find the number of tiles breadth wise:

Number of tiles = 374 ÷ 17 = 22 tiles

Find the total tiles needed:

Total tiles = 34 x 22 = 748

Answer:748 tiles are needed.

Answer 2

Answer:

minimum number of square marbles required to tile a floor of length is 748

Step-by-step explanation:

1m = 100 cm

5m 78 cm = (5 * 100)cm + 78 cm

                 = 578 cm

3m 74 cm = (3 * 100)cm +74 cm

                 = 374 cm

Given: length = 578 cm and width = 374 cm

Finding HCF of length and width as minimum number of tiles is asked

Factors of 578 are 2,17,17

Factors of 374 are 2,11,17

So HCF is 17

Now, the minimum number of tiles length wise = 578 / 17 = 34

Minimum number of tiles width wise = 374 / 17 = 22

Total tiles = 34 × 22 = 748

#SPJ2