Question

What is the minimum possible perimeter of a rectangle whose length and breadth are whole numbers and it has an area of 60 m2?

Answer 1

Answer:

32m

Step-by-step explanation:

Length = l

breadth = b

area= 60

lb=60

If we take l=6 and b=10 then the perimeter obtained would be the minimum.

So the perimeter of rectangle is 2(l+b)

2(10+6)

32 m

Hope this helps you.

Answer 2

The minimum possible perimeter of the rectangle is 2(5+12) = 34 meters.

• We need to calculate the length and width of the rectangle that would reduce its perimeter in order to get the minimal perimeter of a rectangle with a 60 m2 size and whole number dimensions.

• To get the potential dimensions of the rectangle, we first factorise its area. As 22 x 3 x 5 is the prime factorization of 60, the rectangle's potential dimensions are (2, 30), (3, 20), (4, 15), (5, 12), and (6, 10).

• We must select the pair of measurements that are closest together in order to reduce the perimeter. We select the pair (5, 12), which has a product of 60, since we want a whole number length and breadth.

• Although there are other rectangles that might have an area of 60 m2 and a perimeter of 34 m, this one has the smallest measurements for an area of 60 m2, and hence has the shortest perimeter.

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