what is the minimum pressure required to compress 500 decimeter cube or air at 1 bar pressure to 200 decimeter cube at 30 degree Celsius
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p1 = 1 bar
v1 = 500 dm³
p2=?
v2 = 200 dm³
Acc. to Boyle's law,
p1 × v1 = p2 × v2
=> 1 bar × 500 = p2 × 200
=> p2 = 2.5 bar
p2 = 2.5 bar
If this helps u then only mark as brainliest.
v1 = 500 dm³
p2=?
v2 = 200 dm³
Acc. to Boyle's law,
p1 × v1 = p2 × v2
=> 1 bar × 500 = p2 × 200
=> p2 = 2.5 bar
p2 = 2.5 bar
If this helps u then only mark as brainliest.
Answered by
2
Answer:
The pressure will be 2.5 bar.
Explanation:
Referred to the attachment.
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