What is the minimum pressure required to compress 500dm3?
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Question 1
What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?
Answer
Volume of gas(V1) = 500dm3 (given)
Pressure of gas (p1) = 1 bar (given)
Volume of compressed gas (V2) = 200dm3 (given)
Now ,let P2 be the pressure required to compress the gas.
Therefore at constant temperature P1 V1 = P2 V2(Boyle’s Law)
As a result P2 = P1 V1 / V2 = 1 X 500/200 = 2.5 bar
Therefore, the minimum pressure required is 2.5 bar.
What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?
Answer
Volume of gas(V1) = 500dm3 (given)
Pressure of gas (p1) = 1 bar (given)
Volume of compressed gas (V2) = 200dm3 (given)
Now ,let P2 be the pressure required to compress the gas.
Therefore at constant temperature P1 V1 = P2 V2(Boyle’s Law)
As a result P2 = P1 V1 / V2 = 1 X 500/200 = 2.5 bar
Therefore, the minimum pressure required is 2.5 bar.
Answered by
1
HLO MATE HERE U GO
⭐. Given that :
V1 = 500dm^3
V2 = 200dm^3
P1 = 1
P2 = ......?
From boyles law
P1 V1 = P2 V2
==> P2 = P1V1 /V2
==> 1× 500 /200
==> 2.5 bar.
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