What is the minimum pressure required to force the blood from the heart to the top of the head ( vertical distance = 50 cm). the density of the blood is 1.04 g/cm3?
Answers
Answer:
Answer - 5101.2 Pa
Explanation:
P= h×rho×g
=0.5×1040×9.81
=5101.2 pa....
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Given: vertical distance, h = 50 cm
the density of the blood, ρ = 1.04 g/cm³
To Find: Minimum pressure required, P.
Solution:
To calculate P, the formula used:
- P = ρ x g x h
- Here, P is the pressure
ρ is the density
h is the height or vertical distance
g is the acceleration due to gravity i.e. g = 9.8 m/s²
Applying the above formula:
P = ρ x g x h
First, convert 50 cm into m:
1 m = 100cm
100cm = 1m
50cm = (1/100) x 50
= 50 /100
= 1/2
= 0.5m
Now, convert 1.04 g/cm³ into kg/m³:
1 kg/m³ = 0.001 g/cm³
0.001 g/cm³ = 1 kg/m³
1.04 g/cm³ = (1 /0.001) x 1.04
= 1.04 /0.001
= 104 x 1000 / 100
= 104x10
= 1040 kg/m³
Putting the values in the formula for P:
P = 1040 x 9.8 x 0.5
= 1040 x 4.9
= 5096
On round-off 5096:
P = 5.01 x 10² Pa
Hence the minimum pressure required to force the blood is 5.01 x 10² pascel.