what is the minimum resistance which can be made using 5 resistors of 1/5 ohm?
Answers
Answered by
355
You know, equivalent resistance decreases when resistors are joined in parallel.
e.g., 1/Req = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄ + ....... + 1/Rn . While equivalent resistance increases when resistors are joined in series e.g., Req = R₁ + R₂ + R₃ + .... + Rn.
it Means, we can get minimum resistance when all the given resistors will join in parallel. And we can get maximum resistance when all the resistors will join in series .
∴ for finding minimum resistance , we have to join all resistors in parallel.
So , 1/Req = 1/(1/5) + 1/(1/5) + 1/(1/5) + 1/(1/5) + 1/(1/5)
1/Req = 5 + 5 + 5 + 5 + 5 = 25
Req = 1/25 Ω
Hence , minimum resistance = 1/25 Ω
e.g., 1/Req = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄ + ....... + 1/Rn . While equivalent resistance increases when resistors are joined in series e.g., Req = R₁ + R₂ + R₃ + .... + Rn.
it Means, we can get minimum resistance when all the given resistors will join in parallel. And we can get maximum resistance when all the resistors will join in series .
∴ for finding minimum resistance , we have to join all resistors in parallel.
So , 1/Req = 1/(1/5) + 1/(1/5) + 1/(1/5) + 1/(1/5) + 1/(1/5)
1/Req = 5 + 5 + 5 + 5 + 5 = 25
Req = 1/25 Ω
Hence , minimum resistance = 1/25 Ω
Answered by
150
Answer: 1/R = 5 + 5 + 5 + 5 + 5
1/R = 25
R = 1/25 ohm
Explanation:
In order to attain minimum resistance, we need to connect the resistors in a parallel combination
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