Physics, asked by raviraja3729, 8 months ago

What is the minimum resistance which can be made using five resistors each of 8 Ohm?

Answers

Answered by CookCK
0

Answer:

1.6 Ω

Explanation:

Connecting 5 resistors in parallel.

1/Rth = 1/8 + 1/8 + 1/8 + 1/8 + 1/8

        = 5/8

thus Rth = 8/5 = 1.6 Ω

Answered by snigdha7yadav
0

Answer- The minimum resistance of given resisters can only be found out by arranging them in 'parallel combination'-

R1= 8Ω , R2= 8Ω, R3=8Ω, R4=8Ω, R5=8Ω (given)

So, 1/Req=1/R1+1/R2+1/R3+1/R4+1/R5

1/Req= 1/8+1/8+1/8+1/8+1/8

1/Req=5/8

Therefore, Req=8/5=1.6 Ω

Hence, the minimum resistance of given resistors is 1.6Ω......ãñs

(θ‿θ)ʘ‿ʘ

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