What is the minimum resistance which can be made using five resistors each of 8 Ohm?
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Answer:
1.6 Ω
Explanation:
Connecting 5 resistors in parallel.
1/Rth = 1/8 + 1/8 + 1/8 + 1/8 + 1/8
= 5/8
thus Rth = 8/5 = 1.6 Ω
Answered by
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Answer- The minimum resistance of given resisters can only be found out by arranging them in 'parallel combination'-
R1= 8Ω , R2= 8Ω, R3=8Ω, R4=8Ω, R5=8Ω (given)
So, 1/Req=1/R1+1/R2+1/R3+1/R4+1/R5
1/Req= 1/8+1/8+1/8+1/8+1/8
1/Req=5/8
Therefore, Req=8/5=1.6 Ω
Hence, the minimum resistance of given resistors is 1.6Ω......ãñs
(θ‿θ)ʘ‿ʘ
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