What is the minimum resistance which can be made using five resistors each of (1/25) ohm?
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1
Answer:
, from the above explanation it is concluded that if we connect all the five resistors in parallel then the minimum resistor of $\dfrac{1}{{25}}{\text{ }}\Omega $ can be made. Hence, the correct answer is $\dfrac{1}{{25}}{\text{ }}\Omega $ and the correct option is B
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Answer:
minimum resistance if conned in series
=Req=r1+r2+r3+r5+r4
1/25+1/25+1/25+1/25+1/25
=1+1+1+1+1/25
5/25
=1/5ohm
if connect in parallel 5 ohm
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