Question

What is the minimum uncertainty in the position of bullet of mass 5g?

Answer 1

Answer:

Heisenberg's uncertainty principle is

Δx x Δp > or equal to h/2π

first of all we need to find

Δp = mv = (5/1000) x (1) = 5x10^-3 = 0.005

thus Δx = h/2π ÷0.005

Δx = [(6.63x10^-34)/2π ] ÷0.005 = 2.11 x 10^-32

Answer 2

According to uncertainty principle ,

∆x.m∆v = h/4π

∴ ∆v = h/4πm∆x

Here given,

m = 10g = 0.01 kg

∆x = 10⁻⁵ m

h = 6.626 × 10⁻³⁴ J.s

Now, ∆v = 6.626 × 10⁻³⁴/{ 4 × 3.14 × 0.01 × 10⁻⁵ )

= 5.27 × 10⁻²⁸ m/s