Question

What is the minimum value for the expression 2x^2+5x+5?

Answer 1

Answer:

1.875

Step-by-step explanation:

For minimum value 2nd derivative should be greater than 0

Y=2x^2+5x+5

Y'=4x+5

For critical point

Y'=0

4x+5=0

x=-5/4

Y"=4>0

Hence fn has minimum value at x=-5/4

Y(-5/4)=2(-5/4)^2+5(-5/4)+5

=2(25/16)+(-25/4)+5

=(25/8)-25/4+5

=1.875