Question

what is the minimum value of 2^sin²θ+2^cos²θ​

Answer 1

Answer:

Correct Option: C

2 sin²θ + 3cos²θ

= 2 sin²θ + 2cos²θ + cos²θ

= 2 (sin²θ + cos²θ) + cos²θ

= 2 + cos² θ [∵ sin² θ + cos²θ =1]

∵ Minimum value of cos θ = –1

But cos² θ > 0, when θ = 90°

[∵ cos 0° = 1, cos 90° = 0]

∴ Required minimum value = 2 + 0 = 2

Answer 2

Answer:

The minimum value of 2sin ^2theta +3 ciass is 2.

Hope it helps u mate

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