What is the minimum value of 2cos X -3cos^2 X + 5
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6
Step-by-step explanation:
2cosx - 3cos²x +5
-3cos²x+2cosx + 5
-3cos²x + 5cosx - 3cosx + 5
= -cosx(3cosx-5) - 1(3cosx-5)
= (-cosx-1)(3cosx-5)
Either, cosx = -1 Or, cosx = 5/3
cosx = cos180°
x=180°
the minimum value is when cosx will be 180°
Answered by
9
Answer:
answer is 0
Step-by-step explanation:
answer in the attachment
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