What is the minimum value of 4x^ 2-6x+1
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Hii!!!
We can solve this one with parabola function approach, though I think the following will be easier:
y=x^2-4x-5=(x^2-4x+4)-9=(x-2)^2-9, now as (x-2)^2\geq{0} (so min value is 0) then the minimum value of the function is 0-9=-9.
Hope it works!!!
We can solve this one with parabola function approach, though I think the following will be easier:
y=x^2-4x-5=(x^2-4x+4)-9=(x-2)^2-9, now as (x-2)^2\geq{0} (so min value is 0) then the minimum value of the function is 0-9=-9.
Hope it works!!!
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minimum value of any polynomial is minus infinity
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