Math, asked by akshatgupta0302, 1 year ago

What is the minimum value of 4x^ 2-6x+1

Answers

Answered by yashula
0
Hii!!!


We can solve this one with parabola function approach, though I think the following will be easier:

y=x^2-4x-5=(x^2-4x+4)-9=(x-2)^2-9, now as (x-2)^2\geq{0} (so min value is 0) then the minimum value of the function is 0-9=-9.

Hope it works!!!
Answered by tanmaykachroo
0
minimum value of any polynomial is minus infinity
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