what is the minimum value of (sinx+cosx)?
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a*sinx + b*cosx, maximum & minimum value is (+,-)√[a^2+b^2]. As here a=b=1, maximum and minimum value of sinx + cosx = (+,-)√[1^2+1^2], i.e. +√2 is maximum value and -√2 is the minimum value.
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Answer:
hey mate here is your answer
Step-by-step explanation:
● The minimum value of (sinx + cosx) is 1.
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