Math, asked by pp8318190, 6 months ago

what is the minimum



value of the above function
f(x) = (2x-1)² +3​

Answers

Answered by hk250328
1

Step-by-step explanation:

=2x²+1²-2.2x.1

=4x²+1-4x+3

=4x²-4x+4

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Answered by missKRITIKA
3

Answer:

»»————> Here is my answer

\mathcal\red{♥*♡∞:。.。  KRITIKA}

Step-by-step explanation:

f(x) = (2x -1) ² + 3

\underline\green{Finding \: f(x) } :-

  • f(x) = (2x - 1)² + 3
  • f(x) = 2(2x - 1)

\underline\orange{put \: f(x) \: = \: 0}

  • f(x) = 0
  • 2 ( 2x - 1 ) = 0
  • 2x - 1 = 0
  • 2x = 1
  • x = ½

\huge\underline\blue{Minimum \: value} :-

\huge\bold\pink{put } \green{x \: = \: ½}

  • f(½) = [ 2(½) - 1 ]² + 3
  • f(½) = ( 1 - 1 )² + 3
  • f(½) = 3

\huge\bold\red{→} The minimum value = 3

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