what is the minimum value of |x-1||+|x-2|+|x-3|....+|x-10|?
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Answer:
Since there are even number of terms
Hence minimum value occurs at x = 5 & 6
Hence the minimum value
= |5-1|+|5-2|+|5-3|....+|5-10|
= 4 + 3 +2 + 1 + 0 + 1 + 2 +3 + 4 + 5
= 25
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