Math, asked by siri542, 11 months ago

what is the miscellaneous series of 12, 33 , 66, 132 _??? and the options are 1)246 , 2)342 , 3)528 , 4)363​

Answers

Answered by revasingh0806
4

Answer:

4.) 363

Step-by-step explanation:

first term is 12

second term = first term +reverse of first term = 12 + 21 = 33

Third term = second term + reverse of second term = 33 + 33 = 66

fourth term = third term + reverse of third term = 66 + 66 = 132

like this

fifth term = fourth term + reverse of fifth term = 132 + 231 = 363

so answer is 363

Answered by satishkumar52
3

hii here is your answer

we know that

first term is 12

second term = first term + reverse of first term=12+21=33

third term =second term + reverse of second term = 33+33=66

forth term=third term + reverse of third term

=66+66=132

fifth term=forth term + reverse of forth term

=132+231=363

so the answer is 363

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