what is the missing term in the statement m²+8m+12=(m+__) (m+__)??
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Answer:
m²+8m+12=(m+_6_) (m+ _2_)
Step-by-step explanation:
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Answered by
1
Answer:
Step-by-step explanation:
Sum = 8
Product = 12
Factors = 2, 6 {2*6 = 12 & 2+6 = 8}
m² + 8m + 12 = m² + 2m + 6m + 12
=m(m + 2) + 6(m +2)
= (m +2)(m + 6)
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