what is the mistake?
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Hey!!!!
On your very special request, I've come to solve this question on my foreign trip, let's solve
_________________
Let the ten's digit be x and unit digit be y where y > x
Then ATQ,
Original number = 10x + y
Then
=> 7(10x + y) = 4(10y + x)
=> 70x + 7y = 40y + 4x
=> 66x - 33y = 0
=> 2x - y = 0
=> y = 2x -------- (1)
Also, y - x = 3
Substituting (1) in Above equation
=> 2x - x = 3
=> x = 3
Thus y = 2(3)
=> y = 6
Thus Original Number = 36 <<<<<< Answer
___________________
Hope this helps ✌️
Good Morning
On your very special request, I've come to solve this question on my foreign trip, let's solve
_________________
Let the ten's digit be x and unit digit be y where y > x
Then ATQ,
Original number = 10x + y
Then
=> 7(10x + y) = 4(10y + x)
=> 70x + 7y = 40y + 4x
=> 66x - 33y = 0
=> 2x - y = 0
=> y = 2x -------- (1)
Also, y - x = 3
Substituting (1) in Above equation
=> 2x - x = 3
=> x = 3
Thus y = 2(3)
=> y = 6
Thus Original Number = 36 <<<<<< Answer
___________________
Hope this helps ✌️
Good Morning
RishabhBansal:
ok
i know my answer is correct
if the answer was incorrect the person who asked the question could have told me
absolutely right ans
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