Question

what is the modulus of 1-i​

Answer 1

Answer:

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Step-by-step explanation:

|1+i|=((1^2)+(1^2))^1÷2=2^1÷2

1+i is in the form of a+ib where i is a complex number. Modulus is nothing but square root of a square plus b square.

Where b is the coefficient i.

=>sqrt (a^2+b^2)

sqrt means square root

Answer 2

Solution :

Modulus of 1 - i

$\sf \: we \: know \: that \: \\ \sf \: |z| = \sqrt{ {x}^{2} + {y}^{2} } \\ \\ \sf \: \bullet \: x = 1 \\ \sf \: \bullet \:y = i \\ \\\sf \: |z| = \sqrt{1 {}^{2} + {i}^{2} } \\ \\ \bf\: \dag \: i {}^{2} = - 1 \\ \\ \sf \: |z| = \sqrt{1 + 1} \\ \\ \sf \: |z| = \sqrt{2}$

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